1,8x^2=4500

Solution for 1,8x^2=4500 equation:

1.8x^2=4500

We move all terms to the left:

1.8x^2-(4500)=0

a = 1.8; b = 0; c = -4500;
Δ = b2-4ac
Δ = 02-4·1.8·(-4500)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*1.8}=\frac{-180}{3.6}
=-50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*1.8}=\frac{180}{3.6}
=50
$